Arrange the following compounds in decreasing order of their boiling points: \(NH_3\), HF, \(SiH_4\), \(CH_4\)
A.
HF,\(NH_3\), \(SiH_4\), \(CH_4\)
B.
\(CH_4\), \(SiH_4\), HF, \(NH_3\),
C.
\(NH_3\),\(CH_4\), \(SiH_4\), HF
D.
\(CH_4\), \(SiH_4\), \(NH_3\), HF
Correct answer is A
The correct order of boiling points of the compounds \(NH_3\), HF, \(SiH_4\), and \(CH_4\) is HF, \(NH_3\), \(SiH_4\), \(CH_4\).
The correct order of boiling points of the compounds \(NH_3\), HF, \(SiH_4\), and \(CH_4\) is HF, \(NH_3\), \(SiH_4\), \(CH_4\).
The boiling point of a compound is the temperature at which the vapor pressure of the liquid is equal to the atmospheric pressure. The stronger the intermolecular forces, the higher the boiling point.
