Consider the reaction: A + 2B\(_{(g)} \rightleftharpoons&...
Consider the reaction: A + 2B\(_{(g)} \rightleftharpoons \) 2C + D\(_{(g)}\) (\(\Delta\)H = +ve)
What will be the effect of decrease in temperature on the reaction?
Rate of backward reaction will increase
The equilibrium constant will shift
Rates of forward and backward reactions are not affected
Rate of forward reaction will increase
Correct answer is A
The given reaction is endothermic, hence, a decrease in temperature will favor the exothermic side which is the backward reaction.