If the volume of a given mass of a gas at 0ºc is 29.5cm\(^3\). What will be the volume of the gas at 15ºc, given that the pressure remains constant. 

A.

31.6

B.

62.2

C.

32.7

D.

31.1

Correct answer is D

Charles' law is a special case of the ideal gas law in which the pressure of a gas is constant.

Charles's law defines the direct relationship between temperature and volume.

GIVEN DATA: V\(_1\) = 29.5cm\(^3\),  V\(_2\) = ? ,  T\(_1\) = 0ºc or 273k,  T\(_2\) = 15ºc or 288k

\(\frac{V_1}{T_1}\) = \(\frac{V_2}{T_2}\)

V\(_2\) = \(\frac{V_1 x T_2}{T_1}\) → \(\frac{29.5 x 288}{273}\)

V\(_2\) = 31.1cm\(^3\)