John was facing S35°E. If he turned 90° in the anticlockwise direction, find his new direction.
A.
S55°E.
B.
S35°W.
C.
N55°E.
D.
N35°W.
Correct answer is C
Consider |NS|
θ = 180° - (90° + 35°) (sum of angles on a straight line is 180°)
= 180° - 90° - 35°
= 90° - 35°
= 55°
∴ His new bearing is N55°E.