If h(m+n) = m(h+r) find h in terms of m, n and r
\(h=\frac{mr}{2m+n}\)
\(h=\frac{mr}{n+m}\)
\(h=\frac{m+n}{n}\)
\(h=\frac{m+n}{m}\)
\(h=\frac{mr}{n}\)
Correct answer is E
\(h(m+n) = m(h+r)\\ hm+hn=hm+mr\\ hn=mr\\ h=\frac{mr}{n}\)
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