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make x the subject of the relation \(y = \frac{ax^3 - b}{3z}...

make x the subject of the relation $y = \frac{ax^3 - b}{3z}$

A.

x = $\sqrt[3] \frac{ax^3 - b}{3z}$

B.

x = $\sqrt[3] \frac{3yz - b}{a}$

C.

x = $\sqrt[3] \frac{3yz + b}{a}$

D.

x = $\sqrt[3] \frac{3yzb}{a}$

View answer & explanation

Correct answer is C

$y = \frac{ax^3 - b}{3z}$

cross multiply

$ax^3 - b$ = 3yz

$ax^3$ = 3yz + b

divide both sides by a

$x^3 = \frac{3yz + b}{a}$

take cube root of both sides

therefore, x = $\sqrt[3] \frac{3yz + b}{a}$

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