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Make t the subject of k = $m \sqrt \frac{t-p}{r}$ ...

Make t the subject of k = $m \sqrt \frac{t-p}{r}$

A.

$\frac{k^2r + p}{m^2}$

B.

$\frac{k^2r + pm^2}{m^2}$

C.

$\frac{k^2r - p}{m^2}$

D.

$\frac{k^2r + p^2}{m^2}$

View answer & explanation

Correct answer is B

square both sides to remove the square root

k $^2$ = m $^2$ $\frac{t-p}{r}$

$\frac{k^2r}{m^2}$ = t - p

t = $\frac{k^2r}{m^2}$ + p

t = $\frac{k^2r + pm^2}{m^2}$

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