3.0
4.5
3.5
2.5
Correct answer is C
where Log\(_2\) 8√2 → Log\(_2\) √128
→ Log\(_2\) 128\(^\frac{1}{2}\)
= \(\frac{1}{2}\) * (Log\(_2\) 128) → \(\frac{1}{2}\) * (Log\(_2\) 2\(^7\))
= 7 * \(\frac{1}{2}\) * (Log\(_2\) 2)
where (Log\(_2\) 2) = 1
→ 7 * \(\frac{1}{2}\) * 1
= \(\frac{7}{2}\) or 3.5