In the diagram, PQR is a circle with center O. If ∠OPQ = 48°, find the value of M.
A.
96\(^o\)
B.
90\(^o\)
C.
68\(^o\)
D.
42\(^o\)
Correct answer is A
< O\(Q\)P = 48\(^o\) (base angles of isoceles \(\triangle\))
m = 48\(^o\) + 48\(^o\) = 96\(^o\) (exterior angle of a \(\triangle\))