X is a point due east of point Y on a coast: Z is another point on the coast but 6√3km due south of y.
If the distance XZ is 12Km. Calculate the bearing of Z from X
240o
210o
150o
60o
Correct answer is B
Using sinØ = \(\frac{6√3}{12}\) → \(\frac{√3}{2}\)
sinØ = \(\frac{√3}{2}\) or 60°
The bearing of Z from X = [270 - 60]° → 210°