In the diagram, \(\overline{MN}\)//\(\overline{PQ}\), < MNP = 2x, and < NPQ = (3x - 50)°. Find the value of < NPQ
A.
200\(^o\)
B.
100\(^o\)
C.
120\(^o\)
D.
90\(^o\)
Correct answer is B
2x = 3x - 50 alternate angle
50\(^o\) = 3x - 2x
50\(^o\) = x
< NPQ = (3x - 50)\(^o\)
= 3(500)\(^o\) - 50
= 150 - 50 = 100\(^o\)