log10\(^{90}\)
log10\(^{19}\)
log10\(^{9}\)
log10\(^{6}\)
Correct answer is A
1 + 2log\(_{10}^3\)
= log\(_{10}^{10} + log_{10}^{3^2}\)
= log\(_{10}^{10} + log_{10}^{9}\)
= log\(_{10}^{10 \times 90}\) = log\(_{10}^{90}\)
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