In the diagram above, |QR| = 12cm and |QS| = 10cm. If &an...
In the diagram above, |QR| = 12cm and |QS| = 10cm. If ∠PQR = 90°, ∠RSQ = 90° and PSQ is a straight line, find |PS|
3.3cm
4.4cm
5cm
5.5cm
6.6cm
Correct answer is B
PQRQ=RQSQ (Similar triangles)
∴
10 (PS + 10) = 12 \times 12
10 PS + 100 = 144 \implies 10 PS = 44
PS = 4.4 cm
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