5(106)
2(106)
5(105)
2(105)
Correct answer is D
2n = 128
2n = 27
n = 7
(2n - 1)(5n - 2) = (2n - 2.2)(5n - 2) put n = 7
(2n - 1)(5n - 2) = 2(2n - 2 x 5n - 2)
= 2(2 x 5)n - 2
= 2(10n - 2) put n = 7
(2n-1)(5n-2) = 2(105)