\(\frac{4}{3}\)
\(\frac{5}{3}\)
\(\frac{3}{4}\)
\(\frac{3}{5}\)
Correct answer is B
m = 2, n = 1
\(\frac{3m^2 - 2n^2}{m^2 _ mn}\)
= \(\frac{3(2)^2 - 2(1)^2}{2^2 + 2(1)}\)
= \(\frac{12 - 2}{4 + 2} = \frac{10}{6}\)
= \(\frac{5}{3}\)
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