\(\frac{\pi}{2}\)
\(\pi\) - 2
\(\frac{\pi}{3}\)
\(\pi\) + 2
Correct answer is B
∫\(^{\pi}_{2}\)(sec2 x - tan2x)dx ∫\(^{\pi}_{2}\) dx = [X]\(^{\pi}_{2}\) = \(\pi\) - 2 + c when c is an arbitrary constant of integration
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