From two points x and y, 8m apart, and in line with a pole, the angle of elevation of the top of the pole are 30o and 60o respectively. Fins the height of the pole assuming that x, y and the foot of the pole are the same horizontal plane and x and y are on the same side of the pole.
\(\sqrt{6}\)
4\(\sqrt{3}\)
\(\sqrt{3}\)
\(\frac{12}{\sqrt{3}}\)
Correct answer is B
From the diagram, WYZ = 60o, XYW = 180o - 60o
= 120o
LX = 30o
XWY = 180o - 120o + 30o
XWY = 30o
WXY = XYW = 30o
Side XY = YW
YW = 8m, sin 60o = \(\frac{3}{2}\)
∴ sin 60o = \(\frac{h}{YW}\), sin 60o = \(\frac{h}{8}\)
h = 8 x \(\frac{3}{2}\)
= 4\(\sqrt{3}\)