The variance of the scores 1, 2, 3, 4, 5 is
1, 2
1, 4
2.0
3.0
Correct answer is C
\(x\) | 1 | 2 | 3 | 4 | 5 | sum =15 |
\(x - \bar{x}\) | -2 | -1 | 0 | 1 | 2 | |
\((x - \bar{x})^{2}\) | 4 | 1 | 0 | 1 | 4 | 10 |
Mean = \(\frac{15}{5} = 3\)
\(Variance = \frac{\sum (x - \bar{x})^{2}}{n}\)
= \(\frac{10}{5}\)
= \(2.0\)