Points X and Y are 20km North and 9km East of point O, respectively. What is the bearing of Y from X? Correct to the nearest degree.
A.
24°
B.
56°
C.
127°
D.
156°
Correct answer is D
\(\tan \theta = \frac{9}{20} = 0.45\)
\(\theta = \tan^{-1} (0.45) \)
= 24.23°
\(\therefore\) The bearing of Y from X = 180° - 24.23°
= 155.77°
= 156° (to the nearest degree)