412
312
712
514
Correct answer is C
∫2−1(2x2+x)dx
= [2x2+13+x1+12]2−1
= [2x33+x22]2−1
= (2(2)33+222)−(2(−1)33+(−1)22)
= (163+2)−(−23+12)
= 223−(−16)
= 223+16
= 152
= 712
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