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\(\begin{array}{c|c} x & 1 & 2 & 3 & 4 & 5 \\ \hline f & 2 &...

x12345f21212
Find the variance of the frequency distribution above

A.

32

B.

94

C.

52

D.

3

Correct answer is B

xffxˉxx(ˉxx)2f(ˉxx)2122248212111326000414111221024882418

x = fxf

= 248

= 3

Variance (62) = f(ˉxx)2f

= 188

= 94