The diagonal of a square is 60 cm. Calculate its peremeter
A.
20\(\sqrt{2}\)
B.
40\(\sqrt{2}\)
C.
90\(\sqrt{2}\)
D.
120\(\sqrt{2}\)
Correct answer is D
\(60^2 + x^2 + x^2\)
\(360^2 = 2x^2\)
\(x^2\) = 1800
x = \(\sqrt{1800}\)
x = 42.4264
x = 42.4264
perimeter = 4x
= 4 x 42.4264
= 169.7056
= 120\(\sqrt{2}\)
= 120\(\sqrt{2}\)