Given that Y is 20cm on a bearing of 300\(^o\) from x, how far south of y is x?
A.
10cm
B.
15cm
C.
25cm
D.
30cm
Correct answer is A
In \(\bigtriangleup\)YSC, sin 30\(^o\) = \(\frac{YS}{20}\)
|YS| = 20 sin 30\(^o\)
= 20 x 0.5
10m