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Simplify $\sqrt[3]{(64r^{-6})^{\frac{1}{2}}}$ ...

Simplify $\sqrt[3]{(64r^{-6})^{\frac{1}{2}}}$

A.

$\frac{r}{2}$

B.

2r

C.

$\frac{1}{2r}$

D.

$\frac{2}{r}$

View answer & explanation

Correct answer is B

$\sqrt[3]{(64r^{-6})^{\frac{1}{2}}}$

= $((64r^{-6})^{1/_2})^{1/_3}$

= $(64r^{-6})^{1/_6}$

= $64)^{1/_6}(r^{-6})^{1/_6}$

=2/r

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