Find the area and perimeter of a square whose length of diagonals is 20\(\sqrt2\) cm
800 cm\(^2\), 80 cm
400 cm, 80 cm\(^2\)
80 cm, 800 cm\(^2\)
400 cm\(^2\), 80 cm
Correct answer is D
Using Pythagoras theorem
⇒ \((20\sqrt2)2 = x^2 + x^2\)
⇒ 800 = \(2x^2\)
⇒ 400 = \(x^2\)
⇒ x = \(\sqrt400\) = 20 cm
∴ Area of a square = \(x^2 = 20^2 = 400 cm^2\)
∴ Perimeter of a square = 4x = 4 x 20 = 80 cm
Similar Questions
Find the length of a chord which subtends an angle of 90° at the centre of a circle whose radius...
If dy/dx = 2x - 3 and y = 3 when x = 0, find y in terms of x. ...
Solve the inequality 2 - x > x\(^2\). ...
\(\begin{array}{c|c} Scores & 3 & 6 & 5 & 2 \\ \hline Frequency & 2 & 3 &...
At what real value of x do the curves whose equations are y = x3 + x and y = x2 + 1 intersect?...
One factor of \(7x^2 + 33x - 10\) is...
Find the gradient of the line joining the points (3, 2) and (1, 4) ...