70o
60o
55o
42o
Correct answer is B
Perimeter of a sector
= 2r + θ360o x 2 x 227 x 21
64 = 2 x 21 + θ360o x 2 x 227 x 21
64 = 42 + θ360o x 44 x 3
64 - 42 = θ360o x 11 x 3
22 = 33θ90
θ=22×3011
= 60o
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