51 women wore coloured shoes to a party, out of which 21 wore purple and 9 wore white. if a woman is selected at Random. What is the probability that she is wearing neither a purple shoe nor a white shoe?

A.

\(\frac{10}{17}\)

B.

\(\frac{7}{17}\)

C.

\(\frac{20}{51}\)

D.

\(\frac{3}{17}\)

E.

\(\frac{1}{51}\)

Correct answer is B

No of women wearing both purple and white shoes = 21 + 9

= 30 women.

No of women wearing neither purple nor white shoes = 51 - 30

= 21 women

\(\therefore\) Probability of picking a woman wearing neither purple nor white shoes 

= \(\frac{21}{51}\)

= \(\frac{7}{17}\).