51 women wore coloured shoes to a party, out of which 21 ...
51 women wore coloured shoes to a party, out of which 21 wore purple and 9 wore white. if a woman is selected at Random. What is the probability that she is wearing neither a purple shoe nor a white shoe?
1017
717
2051
317
151
Correct answer is B
No of women wearing both purple and white shoes = 21 + 9
= 30 women.
No of women wearing neither purple nor white shoes = 51 - 30
= 21 women
∴ Probability of picking a woman wearing neither purple nor white shoes
= \frac{21}{51}
= \frac{7}{17}.
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