51 women wore coloured shoes to a party, out of which 21 wore purple and 9 wore white. if a woman is selected at Random. What is the probability that she is wearing neither a purple shoe nor a white shoe?
\(\frac{10}{17}\)
\(\frac{7}{17}\)
\(\frac{20}{51}\)
\(\frac{3}{17}\)
\(\frac{1}{51}\)
Correct answer is B
No of women wearing both purple and white shoes = 21 + 9
= 30 women.
No of women wearing neither purple nor white shoes = 51 - 30
= 21 women
\(\therefore\) Probability of picking a woman wearing neither purple nor white shoes
= \(\frac{21}{51}\)
= \(\frac{7}{17}\).