The angle of elevation of the top T of a pole from a point X on the horizontal ground is 32°, if X is 68 m away from the foot F of the pole, calculate the height FT of the pole, correct to one decimal place.

A.

128.3m

B.

108.8m

C.

80.2m

D.

57.7m

E.

42.5m

Correct answer is E

to calculate for the high of the pole, we use sohcahtoa

Let the height of the pole be x.

Tan32º = \(\frac{opp}{adj}\)

Tan32º =  \(\frac{x}{68}\)

x = Tan32º x 68 = 42.5m ( to 1 d.p)