What quantity of heat is required to convert 20 g of ice ...
What quantity of heat is required to convert 20 g of ice at 0 ºC to water at the same temperature? (Specific latent heat of ice = 336 Jg−1)
7.06 x 103J
5.38 x 103J
6.72 x 103J
1.35 x 103J
Correct answer is C
quantity of heat = mass * Specific latent heat → 20 * 336
quantity of heat = 6720j or 6.72 x 103J
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