0.5\(\Omega\)
1\(\Omega\)
2\(\Omega\)
2.5\(\Omega\)
3\(\Omega\)
Correct answer is E
1 = \(\frac{E}{R + r}\) \(\frac{2}{R + 1}\) = 0.5 0.5R = 2 - 0.5 = 1.5 R = \(\frac{1.5}{0.5}\) = 3\(\Omega\)
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