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Subtract 12(a - b - c) from the sum of \(\frac{...

Subtract 12(a - b - c) from the sum of 12(a - b + c) and 12
(a + b - c)

A.

12 (a + b + c)

B.

12 (a - b - c)

C.

12 (a - b + c)

D.

12 (a + b - c)

Correct answer is A

12(a - b + c) + 12(a + b - c) - [12 (a - b - c)]

12a12b+12c+12a+12b12c12a+12b+12c

= 12a+12b+12c

= 12(a+b+c)