The nth term of a sequence is n2 - 6n - 4. Find the sum of the 3rd and 4th terms.

A.

24

B.

23

C.

-24

D.

-25

View answer & explanation

Correct answer is D

n2 - 6n - 4

For the 3rd term,
32 - 6(3) - 4

9 - 18 -4 = -13

For the 4th term,
42 - 6(4) - 4

16 - 24 - 4 = -12

Sum of both terms

-13 - 12 = -25

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