If 2 log x (3\(\frac{3}{8}\)) = 6, find the value of x

A.

\(\frac{3}{2}\)

B.

\(\frac{4}{3}\)

C.

\(\frac{2}{3}\)

D.

\(\frac{1}{2}\)

Correct answer is A

2 log x (3\(\frac{3}{8}\)) = 6(divide both sides by 2)

\(\frac{2 log_x(3 \frac{3}{8})}{2} = \frac{6}{2}\)

\(\log_x \frac{27}{8} = 3\)

\(\frac{27}{8} = x^3\)

\(x^3 = \frac{27}{8}\)

x = \(\sqrt{\frac{27}{8}}\)

= (\(\frac{27}{8}\))\(\frac{1}{3}\)

= \(\frac{(3^3)^{\frac{1}{3}}}{(2^3)^{\frac{1}{3}}}\)

= \(\frac{3}{2}\)