A man kept 6 black, 5 brown and 7 purple shirts in a drawer. What is the probability of his picking a purple shirt with his eyes closed?
\(\frac{1}{7}\)
\(\frac{11}{18}\)
\(\frac{7}{18}\)
\(\frac{7}{11}\)
Correct answer is C
Prob. of purple shirt is \(\frac{7}{18}\)