3\(\frac{5}{12}\)
2\(\frac{7}{12}\)
-4 \(\frac{7}{12}\)
-5 \(\frac{7}{12}\)
Correct answer is C
1\(\frac{3}{4} - (2 \frac{1}{3} + 4)\) = \(\frac{7}{4} - (\frac{7}{3} + \frac{4}{1})\); \(\frac{7 + 12}{3}\)
\(\frac{7}{4} - \frac{19}{3} = \frac{21 + 76}{12}\)
= \(\frac{-55}{12} = -4 \frac{7}{12}\)
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