When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) and E\(_2\) are connected in parallel, combined e.m.f. E is given by
E = E\(_1\) + E\(_2\)
E = \(\frac{E_1}{E_2}\)
\(\frac{1}{E} = \frac{1}{E_1} + \frac{1}{E_2}\)
E = E\(_1\) = E\(_2\)
Correct answer is C
If two cells of equal emf s are connected in parallel then the effective emf is equal to the emf of any one of the cells.