When two cells of negligible internal resistances and equ...
When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) and E\(_2\) are connected in parallel, combined e.m.f. E is given by
E = E\(_1\) + E\(_2\)
E = \(\frac{E_1}{E_2}\)
\(\frac{1}{E} = \frac{1}{E_1} + \frac{1}{E_2}\)
E = E\(_1\) = E\(_2\)
Correct answer is C
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