From the diagram, the correct equation for the refractive index n of the medium is
A.
n = tan i
B.
n = \(\frac{sin i}{sin 90^o}\)
C.
n = \(\frac{sin i}{cos (90^o - i)}\)
D.
n = sin 90oC
Correct answer is A
refractive index(n) = \(\frac{sin i}{sinr}\)
where r = 180-(90+i) → r=90-i
since sin(90-i)=cos i
: refractive index(n) = \(\frac{sin i}{cos i}\)
→ tan i