Simplify \(\frac{2}{2 + x} + \frac{2}{2 - x}\)
\(\frac{4}{4 - x^3}\)
\(\frac{8}{4 - x^2}\)
\(\frac{4x}{4 - x^2}\)
\(\frac{8 - 4x}{4 - x^2}\)
Correct answer is B
\(\frac{2}{2 + x} + \frac{2}{2 - x}\)
\(\frac{2(2 - x) + 2(2 + x)}{(2 + x)(2 - x)} = \frac{4 - 2x + 4 + 2x}{4 - 2x + 2x - x^2}\)
= \(\frac{8}{4 - x^2}\)