The sum of 6 and one-third of x is one more than twice x, find x
x = 7
x = 5
x = 3
x = 2
Correct answer is C
6 = \(\frac{1}{3}x\) = 1 + 2x
6 = 1 = \(\frac{2x}{1} - \frac{x}{3}\)
5 = \(\frac{6x - x}{3} = \frac{5x}{3}\)
5 = \(\frac{5x}{3}\)
3 x 5 = 5x
15 = 5x
x = \(\frac{15}{5}\)
= 3