In the diagram, O is the centre of the circle of the circle, PR is a tangent to the circle at Q < SOQ = 86o. Calculate the value of < SQR.
43o
47o
54o
86o
Correct answer is A
Construction: draw a line from Q to point P and another line from S to point P.
< SOQ = 2< QPS (< at centre is twice < on the circumference)
< QPS \(\frac{86}{2} = 43\)
< SQR = < QPS ( < between a chord and tangent = < in the alternate segment)
< SQR = 43o
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