In the diagram, O is the centre of the circle of the circle, PR is a tangent to the circle at Q < SOQ = 86o. Calculate the value of < SQR.

In the diagram, O is the centre of the circle of the circle, PR is a tangent to the circle at Q < SOQ = 86o. Calculate the value of < SQR.

A.

43o

B.

47o

C.

54o

D.

86o

Correct answer is A

Construction: draw a line from Q to point P and another line from S to point P.

< SOQ = 2< QPS (< at centre is twice < on the circumference)

< QPS \(\frac{86}{2} = 43\)

< SQR = < QPS ( < between a chord and tangent = < in the alternate segment)

< SQR = 43o