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Calculate the mid point of the line segment y - 4x + 3 = 0, ...

Calculate the mid point of the line segment y - 4x + 3 = 0, which lies between the x-axis and y-axis.

A.

(3382)

B.

(3382)

C.

(2222)

D.

(2332)

Correct answer is A

y - 4x + 3 = 0

When y = 0, 0 - 4x + 3 = 0

Then -4x = -3

x = 3/4

So the line cuts the x-axis at point (3/4, 0).

When x = 0, y - 4(0) + 3 = 0

Then y + 3 = 0

y = -3

So the line cuts the y-axis at the point (0, -3)

Hence the midpoint of the line y - 4x + 3 = 0, which lies between the x-axis and the y-axis is;

[12(x1+x2),12(y1+y2)]

[12(34+0),12(0+3)]

[12(34),12(3)]

[38,32]