If M and N are two fixed points in a plane. Find the locus L = [P : PM = PN]
a line equal to MN
line parallel to MN
Perpendicular bisector of MN
A circle centre P, radius MN
Correct answer is C
Locus L = (P : PM = Pn}
For M and N being two fixed points
Since PM = PN, P is equidistant from Mand N, So L must be the perpendicular bisector of the line MN