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Make m the subject of the relation k = \(\frac{m - y}{m + 1}...

Make m the subject of the relation k = $\frac{m - y}{m + 1}$

A.

m = $\frac{y + k^2}{k^2 + 1}$

B.

m = $\frac{y + k^2}{1 - k^2}$

C.

m = $\frac{y - k^2}{k^2 + 1}$

D.

m = $\frac{y - k^2}{1 - k^2}$

View answer & explanation

Correct answer is B

k = $\frac{m - y}{m + 1}$

k $^2$ = $\frac{m - y}{m + 1}$

k $^2$ m + k $^2$ = m - y

k $^2$ + y = m - k $^2$ m

$\frac{k^2 + y}{1 - k^2}$ = m $\frac{(1 - k^2)}{1 - k^2}$

m = $\frac{y + k^2}{1 - k^2}$

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