One bag contains 4 white balls and 2 black balls. Another bag contains 3 white balls and 5 black balls, if one ball is drawn from each bag, what is the probability that both are white?
\(\frac{2}{3}\)
\(\frac{3}{8}\)
\(\frac{7}{24}\)
\(\frac{1}{4}\)
\(\frac{1}{24}\)
Correct answer is D
No explanation has been provided for this answer.