If \(y = x^2 - \frac{1}{x}\). find dy/dx
...If \(y = x^2 - \frac{1}{x}\). find dy/dx
2x - (1/x2)
2x + x2
2x - x2
2x + (1/x2)
Correct answer is D
\(y = x^{2} - \frac{1}{x} = x^{2} - x^{-1}\)
\(\frac{\mathrm d y}{\mathrm d x} = 2x - (- x^{-2})\)
= \(2x + \frac{1}{x^{2}}\)
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