13sin3x
−13sin3x
3 sin 3x
-3 sin 3x
Correct answer is D
y = cos 3x
Let u = 3x so that y = cos u
Now, δyδx=3,
δyδx=−sinu
By the chain rule,
δyδx=δyδu×δuδx
δyδx=(−sinu)(3)
δyδx=−3sinu
δyδx=−3sin3x
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