\(\frac{5}{6}\)
\(\frac{7}{12}\)
\(\frac{5}{12}\)
\(\frac{1}{6}\)
Correct answer is C
let the girls' initial pocket money be whole(1)
\(\frac{1}{4}\) of 1 = books, \(\frac{1}{3}\) of 1 = dress
fraction of her money left = 1 - \(\frac{1}{4}\) - \(\frac{1}{3}\)
= \(\frac{5}{12}\)
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