In the figure, PS = QS = RS and QSR - 100o, find QPR
A.
40o
B.
50o
C.
80o
D.
100o
Correct answer is B
Since PS = QS = RS
S is the centre of circle passing through P, Q, R /PS/ = /RS/ = radius
QPR \(\pm\) \(\frac{100^o}{2}\) = 50o