MN is tangent to the given circle at M, MR and MQ are two chords. IF QNM is 60^o and MNQ is 40^o. Find RMQ

120^o

110^o

60^o

20^o

Correct answer is D

QMN = 60^o

MRQ = 60^o(angle in the alternate segment are equal)

MQN = 80^o(angle sum of a \(\bigtriangleup\) = 180^o)

60 = x = 80^o(exterior angle = sum of opposite interior angles)

x = 80^o - 60^o = 20^o

RMQ = 20^o

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MN is tangent to the given circle at M, MR and MQ are two chords. IF QNM is 60^o and MNQ is 40^o. Find RMQ

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