In the diagram, PQ and RS are chords of a circle centre O which meet at T outside the circle. If TP = 24cm. TQ = 8cm and TS = 12cm, find TR.
A.
16cm
B.
14cm
C.
12cm
D.
8cm
Correct answer is A
PT x QT = TR x TS
24 x 8 = TR x 12
TR = \(\frac{24 \times 8}{12}\)
= = 16cm